Question 691870
(80a^3*b^2-60a^2bc)/(120a^2b^3-90ab^2c)
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Factor numerator and denominator:
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= [20a^2b(4a-3c)] / [30ab^2(4ab-3c)
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Cancel all factors common to numerator and denominator to get:
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= [2a(4a-3c)]/[3b(4ab-3c)]
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Cheers,
Stan H.
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