Question 61955
One type of gasohol is 10% alcohol and another type is 35% alcohol. How much of type must be mixed to obtain 400 gallons of a 25% alcohol mixture?
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Let amount of 10% solution be "x"; amount of alcohol is 0.10x
Amount of 35% solution is "400-x"; amount of alcohol is 0.35(400-x)=140-0.35x
EQUATION:
alcohol + alcohol = 0.25(400)
0.10x+140-0.35x = 100
-0.25x=-40
x=160 gallons (amount of 10% solution)
400-x=240 gallons (amount of 35% solution)
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Cheers,
Stan H.