Question 691552
(ln(x))^2=ln(x)^2 solve for x
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(ln(x))^2 - 2ln(x) = 0
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Factor:
ln(x)[ln(x)-2] = 0
ln(x) = 0 or ln(x) = 2
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x = 1 or x = 100
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Cheers,
Stan H.
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