Question 691513
solve this logarithm for x:
y-3=(1/2)^x-2 
Assume you mean:
{{{y-3 = (1/2)^((x-2))}}}
Start by finding the log of each side
{{{log((y-3)) = log(((1/2)^((x-2))))}}}
the log equiv of exponents
{{{log((y-3)) = (x-2)*log((1/2))}}}
Divide both sides by log(1/2)
{{{log((y-3))/log((1/2))}}} = x - 2
Add 2 to both sides
x = {{{log((y-3))/log((1/2))}}} + 2