Question 61944

2y^4 - 13y^3z - 132y^2z^2

= y^2 (2y^2 - 13yz -132z^2)  [removing the common factor y^2 from all the terms]

= y^2(2y^2 - 24yz + 11yz - 132z^2)  [splitting the middle term]

= y^2[2y(y - 12z) + 11z(y - 12z)]

= y^2[(y - 12z)(2y + 11z)]

= y^2(y - 12z)(2y+ 11z)


Good Luck!!!