Question 691248
A surveyor measures the angle of elevation of eye level to the top of a building 60 metres. If he is standing 40 metres away from the building and is 1.6 metres tall. How tall is the building? 

can you please help me out i dont really get this question? thanks in advance
for the first question it is the distance from his eye to the top of the building is 60 meters
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Draw the picture:
You have a right triangle 
hypotenuse = 60 meters
base = 40 meters
height = sqrt(60^2-40^2) = sqrt(3200) = 40sqrt(2) meters
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Total height of the building is 1.6 meters + 40sqrt(2) meters
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Approximate answer: 1.6+40sqrt(2) = 58.169 meters (height of the bldg)
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Cheers,
Stan H.
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