Question 691270
Solve the equation in the interval [0, 2pi.) 
2 cos2 θ = 2 − cos 2θ
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2cos(2x) = 2 - cos(2x)
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3cos(2x) = 2
cos(2x) = 2/3
2x = cos^-1(2/3)
2x = 0.7859
x = 0.3929
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Cheers,
Stan H.
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