Question 691259
(7/(2+e^-x))=3 
7=3(2+e^-x)
7/3 = 2+e^-x
7/3 - 2 = e^-x
ln(7/3 - 2) = -x
-ln(7/3 - 2) = x
-ln(7/3 - 6/3) = x
-ln(1/3) = x
1.099 = x