Question 690607
Solve using logs.
5^2x = 11 
{{{log(5^(2x))}}} = {{{log(11)}}}
the log equiv of exponents
{{{2x*log(5)}}} = {{{log(11)}}}\
divide both sides by log(5)
2x = {{{log(11)/log(5)}}}
using your calc
2x = 1.489896
x = {{{1.489896/2}}}
x ~ .745
:
;
You can check this on your calc: enter 5^(2*.745), results: 11.00