Question 690908
sine function with amplitude of 4, period of pi, and y-intercept of -3
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y = asin(bx)+c
a = |4| = 4
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Since period = 2(pi)/b = pi
b = 2
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y-int = a*sin(b*0)+c = -3
a*0+c = -3
c = -3
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Equation:
y = 4sin(2x)-3
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{{{graph(400,400,-6,6,-10,10,4sin(2x)-3)}}}
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Cheers,
Stan H.