Question 691174
Factor {{{e^x}}}:

{{{(e^x)(2+4x+x^2-1)=0}}}

{{{(e^x)(x^2+4x+1)=0}}}

{{{e^x}}} is not zero ever, so:

{{{x^2+4x+1=0}}}

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

{{{x = (-4 +- sqrt( 16-4 ))/2 = (-4 +- sqrt( 12 ))/2 = (-4 +- 2sqrt(3))/2 = -2 +- sqrt(3)}}}