<PRE><B>Question 691077</B>
A shipment of 10 replacement computer hard drives contains four that are defective. You are going to purchase two. What is the probability that 
exactly one is defective?
----
# of ways to succeed: 4C1*6C1 = 24
# of possible outcomes: 10C2 = 45
---
P(1 is defective) = 24/45 = 0.5333
Cheers,
Stan H.
==============

.4020
.3200
.3556
.3020
.5333
</PRE>