Question 691016
{{{4^x - 5 < 0 = 4^x < 5 }}}  This is a job for logarithm.  Remember if {{{a^x = b}}} then {{{logbasea(b)=x}}}<P>
{{{4^x < 5 }}} so {{{x<logbase4(5) = x<1.1609640474}}}

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