Question 690974
Solve sin 2x = sin x for x between 0 and 2pi. 
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2sin(x)cos(x) = sinx
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2sin(x)cos(x)-sin(x) = 0
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Factor:
sin(x)[2cos(x)-1) = 0
sin(x) = 0 or cos(x) = 1/2
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x = 0, or 2pi or pi/3 or (5/3)pi
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cheers,
Stan H.
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