Question 61893
f(x)=3x^2(x-5)(2x+9)^3(x-4)
Set each factor = to 0 and solve for x to find the 0's.
{{{3x^2=0}}}
{{{3x^2/3=0/3}}}
{{{x^2=0}}}
{{{sqrt(x^2)=sqrt(0)}}}
{{{x=0}}}
:
x-5=0
x-5+5=0+5
x=5
:
2x+9=0
2x+9-9=0-0
2x/2=-9/2
x=-4.5
:
x-4=0
x-4+4=0+4
x=4
:
I'm not sure what you mean by multipliatee.
The zeroes are: x={0,5,-4.5,4}
Happy Calculating!!!