Question 689453
(7/3)logn(7y) + (2/5)logn (49y^2)
-----
= logn[(7y)^(7/3)] + logn[(7y)^2]^(2/5)
-------
= logn[(7y)^[(7/3)+(4/5)]
-------
= logn[(7y)^(47/15)]
------
= (47/15)*logn(7y)

==================================
Cheers,
Stan H.