Question 690359
{{{3/((2-4i)-(3+2i))}}}
Distribute the negative in the denominator and combine like terms
{{{3/(2-4i-3-2i) = 3/(-1-6i) = 3/(-1(1-6i)) = -3/(1-6i)}}}
Rationalize the denominator
{{{(-3/(1-6i))((1+6i)/(1+6i)) = -3(1+6i)/((1-6i)(1+6i))}}}
In the denominator
(1-6i)(1+6i) ==> foil
1 - 36i^2 
i = {{{sqrt(-1)}}}, so {{{i^2=sqrt(-1)^2=-1}}}
1 - 36(-1) = 1 + 36 = 37
...
In the numerator, distribute the -3
-3(1+6i) = -3 - 18i
...
{{{highlight_green((-3-18i)/37)}}}
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