Question 690227
Use natural log
{{{ln(3^x)=ln(2^(x-1))}}}
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{{{x*ln(3) = (x-1)ln(2)}}}==> distribute the ln(2) on the right
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{{{x*ln(3) = x*ln(2) - ln(2)}}}
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{{{x*ln(3) - x*ln(2) = -ln(2)}}} ==> factor out the x
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{{{x(ln(3)-ln(2))=-ln(2)}}}
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x = {{{(-ln(2))/(ln(3)-ln(2))}}}
x = -1.709511291
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