Question 690158
{{{((5+4i)/(4-i))((4+i)/(4+i))}}}
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{{{((5+4i)(4+i))/((4-i)(4+i))}}}
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numerator {{{5(4) + 5i + 16i + 4i^2}}}
20 + 21i + 4(-1) = 16+21i
denominator {{{16 - i^2}}} = 16 - -1 = 17
{{{highlight_green((16+21i)/17)}}}
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