Question 690010
Use the quadratic formula to solve for d


{{{d = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{d = (-(38)+-sqrt((38)^2-4(12)(30)))/(2(12))}}} Plug in {{{a = 12}}}, {{{b = 38}}}, {{{c = 30}}}


{{{d = (-38+-sqrt(1444-(1440)))/(24)}}}


{{{d = (-38+-sqrt(4))/24}}}


{{{d = (-38+sqrt(4))/24}}} or {{{d = (-38-sqrt(4))/24}}}


{{{d = (-38+2)/24}}} or {{{d = (-38-2)/24}}}


{{{d = -36/24}}} or {{{d = -40/24}}}


{{{d = -3/2}}} or {{{d = -5/3}}}


So the two solutions are {{{d = -3/2}}} or {{{d = -5/3}}}