Question 689998
Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(8)+-sqrt((8)^2-4(1)(12)))/(2(1))}}} Plug in {{{a = 1}}}, {{{b = 8}}}, {{{c = 12}}}


{{{x = (-8+-sqrt(64-(48)))/(2)}}}


{{{x = (-8+-sqrt(16))/2}}}


{{{x = (-8+sqrt(16))/2}}} or {{{x = (-8-sqrt(16))/2}}}


{{{x = (-8+4)/2}}} or {{{x = (-8-4)/2}}}


{{{x = -4/2}}} or {{{x = -12/2}}}


{{{x = -2}}} or {{{x = -6}}}


The two solutions are therefore: {{{x = -2}}} or {{{x = -6}}}