Question 689697

Solve the logarithmic equation algebraically. Show steps

log(64)1/4=x


{{{log (64, (1/4)) = x}}}


{{{64^x = 1/4}}}


{{{(4^3)^x = 4^- 1}}}


{{{4^(3x) = 4^- 1}}}


3x = - 1 ------ As bases are the same, so are their exponents


{{{highlight_green(x = - 1/3)}}}


You can do the check!!


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