Question 689687
Solving equations where the variable is in the argument of a logarithm usually starts with transforming the equation into one of the following forms:
log(expression) = number
or
log(expression) = log(expression)<br>
Your equation is already in the first form. The next step with this form is to rewrite the equation in exponential form. In general {{{log(a, (p)) = q}}} is equivalent to {{{a^q = p}}}. Using this patter on your equation (and the fact the the base of log is 10):
{{{10^(-4) = x}}}
The left side simplifies to:
{{{1/10000 = x}}}