Question 689877
How many different combinations are there for numbers 1-13 to be lined up 4 on a line. No double numbers and lowest number always first. No repeat perms.
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First we choose the 4 numbers to line up, which is C(13,4).

For each of those C(13,4) ways we put the lowest number first.  Then the
remaining 3 numbers can be arranged to the right of the lowest
number in 3! ways.

Answer:   C(13,4)·3! = 715·6 = 4290

Edwin</pre>