Question 689580
How do you solve (7/9)v + 5/12 - (3/18)v ≥ (3/4)v + 1/3? 
:
{{{(7/9)}}}v + {{{5/12}}} - {{{(3/18)}}}v >= {{{(3/4)}}}v + {{{1/3}}} 
We can get rid of all these denominators by multiplying by 36, resulting in
4(7v) + 3(5) - 2(3v) >= 9(3v) + 12
do the math
28v + 15 - 6v >= 27v + 12
Combine like terms
28v - 6v - 27v >= 12 - 15
-5v >= -3
v has to be positive, mult by -1, this reverses the inequality sign:
5v <= 3
v <= {{{3/5}}}