Question 689441
f(x) = x^3-x-1


f(1) = (1)^3-1-1


f(1) = 1-1-1


f(1) = -1


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f(x) = x^3-x-1


f(2) = (2)^3-2-1


f(2) = 8-2-1


f(2) = 5


Since f(1) = -1 and f(2) = 5, we have a change from a negative number to a positive number, so there's a zero between x = 1 and x = 2