Question 689377
1. computer a can process a quantity of data in 6 hours, wile computer b can process the same amount of data in 10 hours how long will it take both machines working together to process the data?


<pre>
We are given computer A's precessing rate as 1 data quantity per 6 hours, or
{{{(1_DATA_QUANTITY)/(6_HOURS)}}} or {{{1/6}}}{{{DATA_QUANTITY/HR)}}}

We are given computer B's precessing rate as 1 data quantity per 10 hours, or
{{{(1_DATA_QUANTITY)/(10_HOURS)}}} or {{{1/10}}}{{{DATA_QUANTITY/HR)}}}


We let X = the number of hours it will take both machines working together to
process the data.

So we can say that their combined filling rate is 1 data quantity per
X hours, or {{{(1_POOL)/(6_HOURS)}}} or {{{1/6}}}{{{POOL/HR)}}}.

The equation comes from:

      {{{(matrix(4,1,

Computer, "A's",processing, rate))}}}{{{""+""}}}{{{(matrix(4,1,

Computer, "B's", processing, rate))}}}{{{""=""}}}{{{(matrix(4,1,

Their, combined, processing, rate))}}}.

              {{{1/6}}}{{{""+""}}}{{{1/10}}}{{{""=""}}}{{{1/X}}}

Solve that by getting an LCD of 30X

Edwin</pre>