Question 689233
You have {{{(5/8)/(5/4)}}}= {{{y/(3/2)}}}

To cross multiply we multiply the denominators (5/4) and (3/2) to the opposite sides (creating a cross) like so:
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step 1: take (5/4) to the right by multiplying (5/4) on both sides
{{{(5/4)*(5/8)/(5/4)}}}= {{{(5/4)*y/(3/2)}}}

(5/4)/(5/4) on the left cancel each other out because it equals 1

{{{(5/8)=(5/4)*y/(3/2)}}}
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step 2: take (3/2) to the left by multiplying (3/2) on both sides
{{{(3/2)*(5/8)=(3/2)*(5/4)*y/(3/2)}}}

(3/2)/(3/2) on the right cancel each other out because it equals 1
 {{{(3/2)*(5/8)=(5/4)*y}}}
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step 3: simplify the left by multiplying numerators and denominators (top and bottom)

{{{(3*5)/(2*8)=(5/4)*y}}}

{{{15/16=(5/4)*y}}}
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step 4: solve for y by multiplying by 4 and dividing by 5 on both sides(also known as multiplying by the reciprocal fraction (4/5)) 

{{{(15/16)*(4/5)=y*(5/4)*(4/5)}}}

{{{((15*4)/(16*5))=((5*4)/(4*5))*y}}}

{{{((15*4)/(5*16))=((5*4)/(5*4))*y}}}

{{{(15/5)*(4/16)= (5/5)*(4/4)*y}}}

{{{(3/1)*(1/4)= (1)*(1)*y}}}

{{{(3/4)= y}}}

{{{y=.75}}}