Question 689005
{{{m^2 + 22m + 121=0}}}........your formula is in {{{am^2+bm+c=0}}} form


{{{m = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} ...in your case {{{a=1}}},{{{b=22}}}, and {{{c=121}}}


{{{m = (-22 +- sqrt( 22^2-4*1*121 ))/(2*1) }}}

{{{m = (-22 +- sqrt( 484-484 ))/2 }}}


{{{m = (-22 +- sqrt( 0 ))/2 }}}

{{{m = (-22 +- 0))/2 }}}

{{{m = -22/2 }}}

{{{m = -11 }}}


{{{ graph( 600, 600, -15, 10, -5, 10, x^2 + 22x + 121) }}}