Question 688891
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600 ounces of 90% copper is 540 ounces of pure copper.  *[tex \LARGE x] ounces of 10% copper is *[tex \LARGE 0.10x] ounces of pure copper.  *[tex \LARGE 600\ +\ x] ounces of 40% copper is *[tex \LARGE 0.40(600\ +\ x)] ounces of pure copper, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.10x\ +\ 540\ =\ 0.40(600\ +\ x)]


Solve for *[tex \LARGE x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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