Question 688878
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Volume is in cubic inches, not square inches.  You can't make a box just by cutting the corners out of a square; you have to fold up the sides.  Given that, you divide *[tex \LARGE 150\ in^3] by *[tex \LARGE 5\ in] to determine that the area of the base of the box must be *[tex \LARGE 30\ in^2].  Since you have cut squares out of the corners of a square, the shape of the base of the manufactured box must also be square.  Therefore the measure of each side of the base is *[tex \LARGE \sqrt{30}\ in].  Since there is a *[tex \LARGE 5\ in] square cut out of each corner of the original square, the original dimension has to be *[tex \LARGE 10\ in] greater than the measure of the side of the base of the manufactured box.  You can do your own arithmetic. 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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