Question 688053
log4(x+1)+ log4 (x-5)=2
log4[(x+1)(x-5)]=log4(16)
(x+1)(x-5)=16
x^2-4x-5=16
x^2-4x-21=0
(x-7(x+3)=0
x=-3 (reject, (x+1)>0)
x=7