Question 688021
Find the slope and y-intercept of the line that is perpendicular to y=3x−4 and passes through the point (6,−7)
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equation of a line: y=mx+b, m=slope, b=y-intercept
slope of given line=3
slope of perpendicular line=-1/3 (negative reciprocal)
equation:
y=-x/3+b
solve for b using coordinates of given point (6,-7)
-7=-6/3+b
-7=-2+b
b=-5
Equation of perpendicular line:
y=-x/3-5
slope of perpendicular line= -1/3
y-intercept of perpendicular line=-5