Question 687977
n P 6 = n(n-1)(n-2)(n-3)(n-4)(n-5)



n P 5 = n(n-1)(n-2)(n-3)(n-4)


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n P 6 = 5*( n P 5 )


n(n-1)(n-2)(n-3)(n-4)(n-5) = 5 * [ n(n-1)(n-2)(n-3)(n-4) ]


n-5 = 5 ... divide both sides by n(n-1)(n-2)(n-3)(n-4), 


this is last step only done if n doesn't equal 0, 1, 2, 3, or 4.


n = 5+5


n = 10


So the answer is n = 10