Question 687969
In the example below give the centre and radius of the circle.
x^2+y^2-2x-6y+1=0
standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of center, r=radius
complete the squares:
x^2-2x+y^2-6y+1=0
(x^2-2x+1)+(y^2-6y+9)=-1+1+9
(x-1^2+(y-3)^2=9
center: (1,3)
radius:&#8730;9=3