Question 687890
Remember the identity {{{sin^2(x) + cos^2(x) = 1}}}<P>
Using the identity {{{sin^2(x) + 3 cos^2(x) =0}}} becomes {{{sin^2(x)+3*(1-sin^2(x)) = 0}}}--->{{{sin^2(x)+3 - 3*sin^2(x)=0}}}--->{{{-2*sin^2(x)+3 =0}}}--->{{{3=2sin^2(x)}}} --->{{{3/2 = sin^2(x)}}}<P>
Take the square root of both sides.<P>
{{{sqrt(3/2) = sin(x) = 1.225}}} or {{{sin(x) = -1.225}}}<P>
That can't be true because sin(x) never exceeds 1 or falls below -1.  So the answer is no solution.
<P>Hope the solution helped.  Sometimes you need more than a solution.  Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.)