Question 687788
a batch of 100 bulbs is known to have 5% defectives. if 10 bulbs are chosen at random, what is the probability that none of them will get defective? what is the probability that exactly two defectives will be found?
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5 bulbs are defective; 95 bulbs are not defective
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# of ways to select 2 defective: 5C2*95C8
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# of ways to select 2 randomly 100C10
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P(select 2 defective) = [5C2*95C8]/100C2 = 0.0702
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Cheers,
Stan H.