Question 687731
Please help me this problem: 
Write an equation for the hyperbola with vertices at (-3,0) and (3,0) and passing through (6,1) 
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Since the vertices are symmetric to (0,0), the center is at the origin.
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Form:
[x^2/a^2] - [y^2/b^2] = 1
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Substitute and solve for "b^2":
[6^2/3^2 - [1^2/b]^2 = 1
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4 - [1/b^2] = 1
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(1/b^2) = 3
b^2 = 1/3
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Equation:
[x^2/9] - [y^2/(1/3)] = 1
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Cheers,
Stan H.