Question 687726
Assuming this is how the question looks in your textbook:


{{{(3x)/4+(2(1-3x))/5}}}


First, determine the LCD of your 2 fractions.  The first multiple each of the denominators have in common is 20.  So, change each denominator to 20, and multiply the numerator of your first fraction by 5, and the numerator of your second fraction by 4:


{{{((5*3x)/20)+(4(2(1-3x))/20)}}}, giving us


{{{((15x)/20)+((8-24x)/20)}}}


Combine everything in the numerators, and place over our denominator, giving us our final answer in simplest form:


{{{(-9x+8)/20}}}