Question 687692
Sketch the region the region that corresponds to each inequality. Then use your graph to determine if (3,-2)is a solution to the inequality and explain : 
A) X- 3Y >/ 3
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y <= (x - 3)/3
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Graph the boundary as a solid line:
Let x = 0, then y = -1
Let x = 3, then y = 0
Plot the 2 points and draw a line thru them>
Shade the half-plane BELOW the boundary since you
want the area LESS than (x-3)/3
Test the point (3,-2)
-2 < (3-3)/3 = 0
True, so the point is a solution of the inequality.
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B) X /< -2
x <= -2
Draw the boundary as a solid line:
x = -2 
Sketch that as a vertical line thru all points where x = -2.
Shade the half-plane to the left of the boundary because
you want x Less than -2.
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(3,-2) is not in the solution set because 3 is not <= -2.
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Cheers,
Stan H.