Question 687526
{{{matrix(2,2,

lim,((n+3)/(n^2+10)),
"n->oo","")}}}

We use the fact that {{{matrix(2,2,

lim,(p/n^q),
"n->oo","")}}} = 0, when p is a non-zero constant, and q>0 
Divide every term top and bottom by the largest power 
of n that occurs, which in nē.

{{{matrix(2,2,

lim,((n/n^2+3/n^2)/(n^2/n^2+10/n^2)),
"n->oo","")}}}{{{""=""}}}{{{matrix(2,2,

lim,((1/n+3/n^2)/(1+10/n^2)),
"n->oo","")}}}{{{""=""}}}{{{(0+0)/(1+0)}}} = 0

If you are required to use the epsilon-delta process,
you can tell me in the thank-you note.

Edwin</pre>