<PRE><B>Question 687285</B>
work out and graph the following:
-contains the point (-3,-8) and is perpendicular to y = -3/4x + 6
:
Find the slope (m2) of the perpendicular line. The relationship between 
perpendicular lines is m1*m2 = -1; m1 = -3/4, find m2
{{{-3/4}}}*m2 = -1
multiply both sides by -{{{4/3}}}, results
m2 = +{{{4/3}}}
:
Find the perpendicular line using the point/slope form: y - y1 = m(x-x1)
where:
x1 = -3; y1 = -8, m = 4/3
y - (-8) = {{{4/3}}}(x - (-3))
y + 8 = {{{4/3}}}(x + 3)
y + 8 = {{{4/3}}}x + 4
y = {{{4/3}}}x + 4 - 8
y = {{{4/3}}}x - 4
:
Plot these two equations
y = {{{-3/4)x + 6
Table
 x | y
-------
 0 | 6
 4 | 3
 8 | 0
and
y = {{{4/3}}}x - 4
Table
 x | y
-------
 0 |-4
 6 |+4
 9 |+8
:
:
Should look like this:
{{{ graph( 300, 300, -10, 12, -10, 10, -.75x+6, (4/3)x-4 ) }}}

</PRE>