Question 687121
If you're talking about {{{4^(x+3)-1}}}, the range is {{{y > -1}}} because the range of the parent function {{{4^x}}} is {{{y > 0}}} (since {{{4^x}}} is always positive). Then you shift it down 1 unit to get {{{4^x-1}}} and this alters the range to become {{{y > -1}}}