Question 687075


{{{3a^3+2a^2+6a+4}}} Start with the given expression



{{{(3a^3+2a^2)+(6a+4)}}} Group the terms in two pairs



{{{a^2(3a+2)+2(3a+2)}}} Factor out the GCF {{{a^2}}} out of the first group. Factor out the GCF {{{2}}} out of the second group



{{{(a^2+2)(3a+2)}}} Since we have the common term {{{3a+2}}}, we can combine like terms



So {{{3a^3+2a^2+6a+4}}} factors to {{{(a^2+2)(3a+2)}}}



In other words, {{{3a^3+2a^2+6a+4=(a^2+2)(3a+2)}}}