Question 686673
solve the following equation:
ln2-ln(3x+2)=1 
We can write this as single log, (- means divide)
{{{ln(2/((3n+2)))}}} = 1
Write the exponent equiv
{{{2/((3n+2))}}} = {{{e^1}}}
which is
3x + 2 = {{{2/e}}}
find the value with a calc
3x + 2 = .73576
3x = -2 + .73576
3x = -1.26424
x = -1.26424/3
x = -.4214