Question 686433
{{{3x^2+8x=11}}}


{{{3x^2+8x-11 = 0}}}


Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(8)+-sqrt((8)^2-4(3)(-11)))/(2(3))}}} Plug in {{{a = 3}}}, {{{b = 8}}}, {{{c = -11}}}


{{{x = (-8+-sqrt(64-(-132)))/(6)}}}


{{{x = (-8+-sqrt(64+132))/(6)}}}


{{{x = (-8+-sqrt(196))/6}}}


{{{x = (-8+sqrt(196))/6}}} or {{{x = (-8-sqrt(196))/6}}}


{{{x = (-8+14)/6}}} or {{{x = (-8-14)/6}}}


{{{x = 6/6}}} or {{{x = -22/6}}}


{{{x = 1}}} or {{{x = -11/3}}}


So the two solutions are {{{x = 1}}} or {{{x = -11/3}}}