Question 686452
simplify the expression: 
ln(x)+log (in base 2) of x^2
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= ln(x) + [ln(x^2)/ln(2)
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= [ln(2)*ln(x) + ln(x^2)'/ln(2)
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= [ln(x^(ln(2))( + ln(x^2)]/ln(2)
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= ln[x^2*x^(ln(2))]/ln(2)
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= ln[x^(2+ln(2))/ln(2)
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= log2[x^(2+ln(2))]
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Cheers,
Stan H.