Question 685951
How do i do |3x-1|+10=12 ?
First isolate the absolute value.
|3x-1|+10-10=12-10
|3x-1|=2
Then because the stuff inside of the absolute value can be + or - 2 to get 2, you set the inside equal to them both and solve 2 equations.
{{{3x-1=-2}}} or {{{3x-1=2}}}
{{{3x-1+1=-2+1}}} or {{{3x-1+1=2+1}}}
{{{3x=-1}}} or {{{3x=3}}}
{{{3x/3=-1/3}}} or {{{3x/3=3/3}}}
{{{highlight(x=-1/3)}}} or {{{highlight(x=1)}}}
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It seems not to make sense to do that...but let's check to see that both answers are correct:
for x=-1/3
|3(-1/3)-1|+10=12
|-1-1|+10=12
|-2|+10=12
12=12 True....so x=-1/3 for sure.
for x=1
|3(1)-1|+10=12
|3-1|+10=12
|2|+10=12
2+10=12
12=12 True....so x also can = 1
Often teaches want set notation of x={-1/3,1}
Happy Calculating!!!