Question 685906
Which of the following inequalities satisfies the following description: the region inside an ellipse centered at the origin, with x-intercepts at -2 and 2, and y-intercepts at 4 and -4?
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Ans: x^2/4 + y^2/16 < 1
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Graph the solution set of the system of inequalities. 
3x - 2y &#8805; -6
x - 1 < 0
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y <= (3/2)x +3
x < 1
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The graph shows the region of feasible solutions. Find the maximum or minimum value, as specified, of the objective function. 
objective function = x - 4y; minimum
(I am pretty sure you have to have the graph for this one, so I will keep trying to learn this myself :S)
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Comment: Find the coordinates of each corner of the region of feasible
solution.  Substitute each of the x/y pairs into x - 4y to find the
minimum.
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Provide an appropriate response. 
Which one of the following is a description of the graph of the inequality?
(x - 7)2 + (y + 8)2 > 36
Answers ???
a.The region inside the circle with center (-7, 8) and radius 6
b.The region outside a circle with center (-7, 8) and radius 6
c.The region outside a circle with center (7, -8) and radius 6
d.The region inside a circle with center (7, -8) and radius 6
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Center at (7,-8); region outside because of ">".
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Graph the inequality. 
(x - 4)^2 + (y + 3)^2 &#8804; 4
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Circle with center at (4,-3) and radius = sqrt(4) = 2
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Shade the area inside the circle.
Graph is every point on the circle and inside the circle.
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Cheers,
Stan H.
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