Question 685898

{{{(3/4)x^4-3x^2=0}}}

{{{3x^4/4-3x^2=0}}}

{{{x^2(x^2/4-3)=0}}}

{{{x^2(x^2/4-3*4/4)=0}}}

{{{x^2(x^2/4-12/4)=0}}}

{{{x^2((x^2-12)/4)=0}}}

{{{(x^2/4)(x^2-12)=0}}}

solutions:

if {{{x^2/4=0}}}.....=>{{{x^2=0*4}}}....=>{{{x^2=0}}}...=>{{{x=0}}}

so, first and second solutions are {{{x=0}}}

if {{{x^2-12=0}}}.....=>... {{{x^2=12}}}..=>... {{{x=sqrt(12)}}}=>... {{{x=3.46}}} or {{{x=-3.46}}}

{{{ graph( 600, 600, -10, 10, -10, 10,x^2(x^2/4-3)) }}}